13435250441 has 2 divisors, whose sum is σ = 13435250442. Its totient is φ = 13435250440.

The previous prime is 13435250359. The next prime is 13435250473. The reversal of 13435250441 is 14405253431.

It is an a-pointer prime, because the next prime (13435250473) can be obtained adding 13435250441 to its sum of digits (32).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9222721225 + 4212529216 = 96035^2 + 64904^2 .

It is an emirp because it is prime and its reverse (14405253431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13435250441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13435250398 and 13435250407.

It is not a weakly prime, because it can be changed into another prime (13435250141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717625220 + 6717625221.

It is an arithmetic number, because the mean of its divisors is an integer number (6717625221).

Almost surely, 2^13435250441 is an apocalyptic number.

It is an amenable number.

13435250441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13435250441 is an equidigital number, since it uses as much as digits as its factorization.

13435250441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 32.

The spelling of 13435250441 in words is "thirteen billion, four hundred thirty-five million, two hundred fifty thousand, four hundred forty-one".