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13436508221 is a prime number
BaseRepresentation
bin11001000001110000…
…01101100000111101
31021200102011100011122
430200320031200331
5210004221230341
610101143000325
7653653302233
oct144070154075
937612140148
1013436508221
115775616554
12272ba390a5
1313619566a6
14916714953
1553992794b
hex320e0d83d

13436508221 has 2 divisors, whose sum is σ = 13436508222. Its totient is φ = 13436508220.

The previous prime is 13436508199. The next prime is 13436508223. The reversal of 13436508221 is 12280563431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13429564996 + 6943225 = 115886^2 + 2635^2 .

It is an emirp because it is prime and its reverse (12280563431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13436508221 - 214 = 13436491837 is a prime.

Together with 13436508223, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13436508223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6718254110 + 6718254111.

It is an arithmetic number, because the mean of its divisors is an integer number (6718254111).

Almost surely, 213436508221 is an apocalyptic number.

It is an amenable number.

13436508221 is a deficient number, since it is larger than the sum of its proper divisors (1).

13436508221 is an equidigital number, since it uses as much as digits as its factorization.

13436508221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 35.

The spelling of 13436508221 in words is "thirteen billion, four hundred thirty-six million, five hundred eight thousand, two hundred twenty-one".