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134371066434371 = 13231193132892373
BaseRepresentation
bin11110100011010110110011…
…101011101101001101000011
3122121202202012122122221020222
4132203112303223231031003
5120103013421001344441
61153441114333253255
740205663201314064
oct3643266353551503
9577682178587228
10134371066434371
11398a64a3a57088
12130a201a33422b
1359c91a2554900
142527846b3856b
151080476c78d4b
hex7a35b3aed343

134371066434371 has 24 divisors (see below), whose sum is σ = 150974241975936. Its totient is φ = 119411769784320.

The previous prime is 134371066434317. The next prime is 134371066434379. The reversal of 134371066434371 is 173434660173431.

It is not a de Polignac number, because 134371066434371 - 210 = 134371066433347 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134371066434379) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 65435060 + ... + 67457313.

It is an arithmetic number, because the mean of its divisors is an integer number (6290593415664).

Almost surely, 2134371066434371 is an apocalyptic number.

134371066434371 is a deficient number, since it is larger than the sum of its proper divisors (16603175541565).

134371066434371 is a wasteful number, since it uses less digits than its factorization.

134371066434371 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132892623 (or 132892610 counting only the distinct ones).

The product of its (nonzero) digits is 9144576, while the sum is 53.

The spelling of 134371066434371 in words is "one hundred thirty-four trillion, three hundred seventy-one billion, sixty-six million, four hundred thirty-four thousand, three hundred seventy-one".

Divisors: 1 13 31 169 193 403 2509 5239 5983 32617 77779 1011127 132892373 1727600849 4119663563 22458811037 25648227989 53555626319 333426963857 696223142147 795095067659 4334550530141 10336235879567 134371066434371