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1343845242671 is a prime number
BaseRepresentation
bin10011100011100011011…
…010110001011100101111
311202110200212220120000212
4103203203122301130233
5134004143340231141
62505204243213035
7166042511043251
oct23434332613457
94673625816025
101343845242671
11478a15672a38
1219854307717b
13999549c5009
1449084703cd1
1524e532b32eb
hex138e36b172f

1343845242671 has 2 divisors, whose sum is σ = 1343845242672. Its totient is φ = 1343845242670.

The previous prime is 1343845242653. The next prime is 1343845242689. The reversal of 1343845242671 is 1762425483431.

It is a balanced prime because it is at equal distance from previous prime (1343845242653) and next prime (1343845242689).

It is a cyclic number.

It is not a de Polignac number, because 1343845242671 - 238 = 1068967335727 is a prime.

It is a super-3 number, since 3×13438452426713 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343845242071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671922621335 + 671922621336.

It is an arithmetic number, because the mean of its divisors is an integer number (671922621336).

Almost surely, 21343845242671 is an apocalyptic number.

1343845242671 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343845242671 is an equidigital number, since it uses as much as digits as its factorization.

1343845242671 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3870720, while the sum is 50.

The spelling of 1343845242671 in words is "one trillion, three hundred forty-three billion, eight hundred forty-five million, two hundred forty-two thousand, six hundred seventy-one".