1343996117 has 2 divisors, whose sum is σ = 1343996118. Its totient is φ = 1343996116.

The previous prime is 1343996107. The next prime is 1343996119. The reversal of 1343996117 is 7116993431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 679697041 + 664299076 = 26071^2 + 25774^2 .

It is a cyclic number.

It is not a de Polignac number, because 1343996117 - 2³⁰ = 270254293 is a prime.

It is a super-2 number, since 2×1343996117² = 3612651125022155378, which contains 22 as substring.

Together with 1343996119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343996119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671998058 + 671998059.

It is an arithmetic number, because the mean of its divisors is an integer number (671998059).

Almost surely, 2^1343996117 is an apocalyptic number.

It is an amenable number.

1343996117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343996117 is an equidigital number, since it uses as much as digits as its factorization.

1343996117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 122472, while the sum is 44.

The square root of 1343996117 is about 36660.5526008542. The cubic root of 1343996117 is about 1103.5686077635.

The spelling of 1343996117 in words is "one billion, three hundred forty-three million, nine hundred ninety-six thousand, one hundred seventeen".