Base | Representation |
---|---|
bin | 1100001110010100101110… |
… | …0011010000100011011011 |
3 | 1202120212120001110220210212 |
4 | 3003211023203100203123 |
5 | 3230201032333000402 |
6 | 44330204003201335 |
7 | 2555011120524206 |
oct | 303451343204333 |
9 | 52525501426725 |
10 | 13440220203227 |
11 | 4311a68a12074 |
12 | 161097a67624b |
13 | 76653ab8807c |
14 | 34671db1693d |
15 | 184927062952 |
hex | c394b8d08db |
13440220203227 has 2 divisors, whose sum is σ = 13440220203228. Its totient is φ = 13440220203226.
The previous prime is 13440220203217. The next prime is 13440220203353. The reversal of 13440220203227 is 72230202204431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13440220203227 - 28 = 13440220202971 is a prime.
It is a super-2 number, since 2×134402202032272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13440220203193 and 13440220203202.
It is not a weakly prime, because it can be changed into another prime (13440220203217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720110101613 + 6720110101614.
It is an arithmetic number, because the mean of its divisors is an integer number (6720110101614).
Almost surely, 213440220203227 is an apocalyptic number.
13440220203227 is a deficient number, since it is larger than the sum of its proper divisors (1).
13440220203227 is an equidigital number, since it uses as much as digits as its factorization.
13440220203227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 32.
Adding to 13440220203227 its reverse (72230202204431), we get a palindrome (85670422407658).
The spelling of 13440220203227 in words is "thirteen trillion, four hundred forty billion, two hundred twenty million, two hundred three thousand, two hundred twenty-seven".
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