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13440220203353 is a prime number
BaseRepresentation
bin1100001110010100101110…
…0011010000100101011001
31202120212120001110220222112
43003211023203100211121
53230201032333001403
644330204003202105
72555011120524446
oct303451343204531
952525501426875
1013440220203353
114311a68a12179
12161097a676335
1376653ab88148
1434671db169cd
151849270629d8
hexc394b8d0959

13440220203353 has 2 divisors, whose sum is σ = 13440220203354. Its totient is φ = 13440220203352.

The previous prime is 13440220203227. The next prime is 13440220203391. The reversal of 13440220203353 is 35330202204431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10702823481289 + 2737396722064 = 3271517^2 + 1654508^2 .

It is a cyclic number.

It is not a de Polignac number, because 13440220203353 - 210 = 13440220202329 is a prime.

It is a super-2 number, since 2×134402202033532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13440220203653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720110101676 + 6720110101677.

It is an arithmetic number, because the mean of its divisors is an integer number (6720110101677).

Almost surely, 213440220203353 is an apocalyptic number.

It is an amenable number.

13440220203353 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440220203353 is an equidigital number, since it uses as much as digits as its factorization.

13440220203353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 32.

Adding to 13440220203353 its reverse (35330202204431), we get a palindrome (48770422407784).

The spelling of 13440220203353 in words is "thirteen trillion, four hundred forty billion, two hundred twenty million, two hundred three thousand, three hundred fifty-three".