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13440302011427 is a prime number
BaseRepresentation
bin1100001110010101000001…
…1011010101010000100011
31202120212202202102012120012
43003211100123111100203
53230201214303331202
644330220044435135
72555013133061114
oct303452033252043
952525682365505
1013440302011427
114312000108855
1216109a1b48aab
13766551acc4a5
1434672a93020b
1518492e322152
hexc39506d5423

13440302011427 has 2 divisors, whose sum is σ = 13440302011428. Its totient is φ = 13440302011426.

The previous prime is 13440302011397. The next prime is 13440302011459. The reversal of 13440302011427 is 72411020304431.

It is an a-pointer prime, because the next prime (13440302011459) can be obtained adding 13440302011427 to its sum of digits (32).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13440302011427 - 222 = 13440297817123 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13440302011393 and 13440302011402.

It is not a weakly prime, because it can be changed into another prime (13440302019427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720151005713 + 6720151005714.

It is an arithmetic number, because the mean of its divisors is an integer number (6720151005714).

Almost surely, 213440302011427 is an apocalyptic number.

13440302011427 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440302011427 is an equidigital number, since it uses as much as digits as its factorization.

13440302011427 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 32.

Adding to 13440302011427 its reverse (72411020304431), we get a palindrome (85851322315858).

The spelling of 13440302011427 in words is "thirteen trillion, four hundred forty billion, three hundred two million, eleven thousand, four hundred twenty-seven".