Base | Representation |
---|---|
bin | 101000000011100… |
… | …0100100000110101 |
3 | 10110200000211121112 |
4 | 1100013010200311 |
5 | 10223032441043 |
6 | 341211124405 |
7 | 45210034031 |
oct | 12007044065 |
9 | 3420024545 |
10 | 1344030773 |
11 | 62a741238 |
12 | 316143705 |
13 | 1855b33a7 |
14 | ca7031c1 |
15 | 7cedb518 |
hex | 501c4835 |
1344030773 has 2 divisors, whose sum is σ = 1344030774. Its totient is φ = 1344030772.
The previous prime is 1344030707. The next prime is 1344030827. The reversal of 1344030773 is 3770304431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 899580049 + 444450724 = 29993^2 + 21082^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344030773 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344030173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672015386 + 672015387.
It is an arithmetic number, because the mean of its divisors is an integer number (672015387).
Almost surely, 21344030773 is an apocalyptic number.
It is an amenable number.
1344030773 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344030773 is an equidigital number, since it uses as much as digits as its factorization.
1344030773 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21168, while the sum is 32.
The square root of 1344030773 is about 36661.0252584403. The cubic root of 1344030773 is about 1103.5780931443.
The spelling of 1344030773 in words is "one billion, three hundred forty-four million, thirty thousand, seven hundred seventy-three".
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