Base | Representation |
---|---|
bin | 1100001110010101100010… |
… | …1111001001100110101111 |
3 | 1202120220010110202010002001 |
4 | 3003211120233021212233 |
5 | 3230202011001034203 |
6 | 44330241544513131 |
7 | 2555016445054465 |
oct | 303453057114657 |
9 | 52526113663061 |
10 | 13440441424303 |
11 | 4312071879803 |
12 | 1610a2077b7a7 |
13 | 76657496250a |
14 | 346741260835 |
15 | 18493b6ae91d |
hex | c3958bc99af |
13440441424303 has 2 divisors, whose sum is σ = 13440441424304. Its totient is φ = 13440441424302.
The previous prime is 13440441424243. The next prime is 13440441424307. The reversal of 13440441424303 is 30342414404431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13440441424303 - 29 = 13440441423791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13440441424307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720220712151 + 6720220712152.
It is an arithmetic number, because the mean of its divisors is an integer number (6720220712152).
Almost surely, 213440441424303 is an apocalyptic number.
13440441424303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13440441424303 is an equidigital number, since it uses as much as digits as its factorization.
13440441424303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 221184, while the sum is 37.
Adding to 13440441424303 its reverse (30342414404431), we get a palindrome (43782855828734).
The spelling of 13440441424303 in words is "thirteen trillion, four hundred forty billion, four hundred forty-one million, four hundred twenty-four thousand, three hundred three".
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