134404431253501 has 2 divisors, whose sum is σ = 134404431253502. Its totient is φ = 134404431253500.

The previous prime is 134404431253489. The next prime is 134404431253513. The reversal of 134404431253501 is 105352134404431.

It is a balanced prime because it is at equal distance from previous prime (134404431253489) and next prime (134404431253513).

It can be written as a sum of positive squares in only one way, i.e., 133415182201401 + 989249052100 = 11550549^2 + 994610^2 .

It is a cyclic number.

It is not a de Polignac number, because 134404431253501 - 2¹³ = 134404431245309 is a prime.

It is a super-2 number, since 2×134404431253501² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134404431253801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67202215626750 + 67202215626751.

It is an arithmetic number, because the mean of its divisors is an integer number (67202215626751).

Almost surely, 2^{134404431253501} is an apocalyptic number.

It is an amenable number.

134404431253501 is a deficient number, since it is larger than the sum of its proper divisors (1).

134404431253501 is an equidigital number, since it uses as much as digits as its factorization.

134404431253501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 40.

Adding to 134404431253501 its reverse (105352134404431), we get a palindrome (239756565657932).

The spelling of 134404431253501 in words is "one hundred thirty-four trillion, four hundred four billion, four hundred thirty-one million, two hundred fifty-three thousand, five hundred one".