1344049541 has 2 divisors, whose sum is σ = 1344049542. Its totient is φ = 1344049540.

The previous prime is 1344049523. The next prime is 1344049543. The reversal of 1344049541 is 1459404431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1098657316 + 245392225 = 33146^2 + 15665^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1344049541 is a prime.

Together with 1344049543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1344049543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672024770 + 672024771.

It is an arithmetic number, because the mean of its divisors is an integer number (672024771).

Almost surely, 2^1344049541 is an apocalyptic number.

It is an amenable number.

1344049541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344049541 is an equidigital number, since it uses as much as digits as its factorization.

1344049541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 35.

The square root of 1344049541 is about 36661.2812242016. The cubic root of 1344049541 is about 1103.5832298960.

The spelling of 1344049541 in words is "one billion, three hundred forty-four million, forty-nine thousand, five hundred forty-one".