Base | Representation |
---|---|
bin | 101000000011100… |
… | …1011101100100101 |
3 | 10110200002022222022 |
4 | 1100013023230211 |
5 | 10223034411242 |
6 | 341211512525 |
7 | 45210215564 |
oct | 12007135445 |
9 | 3420068868 |
10 | 1344060197 |
11 | 62a761357 |
12 | 316158745 |
13 | 1855c38bc |
14 | ca70dbdb |
15 | 7cee50d2 |
hex | 501cbb25 |
1344060197 has 2 divisors, whose sum is σ = 1344060198. Its totient is φ = 1344060196.
The previous prime is 1344060191. The next prime is 1344060199. The reversal of 1344060197 is 7910604431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1175735521 + 168324676 = 34289^2 + 12974^2 .
It is a cyclic number.
It is not a de Polignac number, because 1344060197 - 24 = 1344060181 is a prime.
Together with 1344060199, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344060191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672030098 + 672030099.
It is an arithmetic number, because the mean of its divisors is an integer number (672030099).
Almost surely, 21344060197 is an apocalyptic number.
It is an amenable number.
1344060197 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344060197 is an equidigital number, since it uses as much as digits as its factorization.
1344060197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 35.
The square root of 1344060197 is about 36661.4265543500. The cubic root of 1344060197 is about 1103.5861463936.
It can be divided in two parts, 13440 and 60197, that added together give a palindrome (73637).
The spelling of 1344060197 in words is "one billion, three hundred forty-four million, sixty thousand, one hundred ninety-seven".
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