Base | Representation |
---|---|
bin | 111110100101110000… |
… | …1010110101111110100 |
3 | 110211221100001100022002 |
4 | 1331023201112233310 |
5 | 4200233210140200 |
6 | 141425250354432 |
7 | 12465554554523 |
oct | 1751341265764 |
9 | 424840040262 |
10 | 134411021300 |
11 | 52004576786 |
12 | 22071b8ba18 |
13 | c8a09c61ca |
14 | 67112524ba |
15 | 376a227bd5 |
hex | 1f4b856bf4 |
134411021300 has 18 divisors (see below), whose sum is σ = 291671916438. Its totient is φ = 53764408480.
The previous prime is 134411021273. The next prime is 134411021309. The reversal of 134411021300 is 3120114431.
It can be written as a sum of positive squares in 3 ways, for example, as 1509944164 + 132901077136 = 38858^2 + 364556^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134411021309) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 672055007 + ... + 672055206.
Almost surely, 2134411021300 is an apocalyptic number.
134411021300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
134411021300 is an abundant number, since it is smaller than the sum of its proper divisors (157260895138).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134411021300 is a wasteful number, since it uses less digits than its factorization.
134411021300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1344110227 (or 1344110220 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 134411021300 its reverse (3120114431), we get a palindrome (137531135731).
The spelling of 134411021300 in words is "one hundred thirty-four billion, four hundred eleven million, twenty-one thousand, three hundred".
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