Base | Representation |
---|---|
bin | 10011100011110011110… |
… | …011011011011110100101 |
3 | 11202111102001011212122121 |
4 | 103203303303123132211 |
5 | 134010224224013413 |
6 | 2505251423225541 |
7 | 166052356460245 |
oct | 23436363333645 |
9 | 4674361155577 |
10 | 1344120141733 |
11 | 479046862746 |
12 | 1985bb1482b1 |
13 | 99999944995 |
14 | 490ad021b25 |
15 | 24e6c4b4b8d |
hex | 138f3cdb7a5 |
1344120141733 has 2 divisors, whose sum is σ = 1344120141734. Its totient is φ = 1344120141732.
The previous prime is 1344120141691. The next prime is 1344120141799. The reversal of 1344120141733 is 3371410214431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1108120444929 + 235999696804 = 1052673^2 + 485798^2 .
It is a cyclic number.
It is not a de Polignac number, because 1344120141733 - 213 = 1344120133541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344120241733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672060070866 + 672060070867.
It is an arithmetic number, because the mean of its divisors is an integer number (672060070867).
Almost surely, 21344120141733 is an apocalyptic number.
It is an amenable number.
1344120141733 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344120141733 is an equidigital number, since it uses as much as digits as its factorization.
1344120141733 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 34.
The spelling of 1344120141733 in words is "one trillion, three hundred forty-four billion, one hundred twenty million, one hundred forty-one thousand, seven hundred thirty-three".
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