Base | Representation |
---|---|
bin | 101000000011101… |
… | …1101110000000011 |
3 | 10110200020002102012 |
4 | 1100013131300003 |
5 | 10223044243042 |
6 | 341213243135 |
7 | 45210644306 |
oct | 12007356003 |
9 | 3420202365 |
10 | 1344134147 |
11 | 62a801974 |
12 | 3161934ab |
13 | 18561b465 |
14 | ca72cb3d |
15 | 7d00be82 |
hex | 501ddc03 |
1344134147 has 2 divisors, whose sum is σ = 1344134148. Its totient is φ = 1344134146.
The previous prime is 1344134117. The next prime is 1344134149. The reversal of 1344134147 is 7414314431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1344134147 - 216 = 1344068611 is a prime.
Together with 1344134149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1344134149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672067073 + 672067074.
It is an arithmetic number, because the mean of its divisors is an integer number (672067074).
Almost surely, 21344134147 is an apocalyptic number.
1344134147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344134147 is an equidigital number, since it uses as much as digits as its factorization.
1344134147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16128, while the sum is 32.
The square root of 1344134147 is about 36662.4350937032. The cubic root of 1344134147 is about 1103.6063857398.
Adding to 1344134147 its reverse (7414314431), we get a palindrome (8758448578).
The spelling of 1344134147 in words is "one billion, three hundred forty-four million, one hundred thirty-four thousand, one hundred forty-seven".
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