Base | Representation |
---|---|
bin | 11110100011111111000111… |
… | …001000011010110001001100 |
3 | 122121220212220122000211021112 |
4 | 132203333013020122301030 |
5 | 120104221033123313400 |
6 | 1153513032455351152 |
7 | 40212054465052226 |
oct | 3643770710326114 |
9 | 577825818024245 |
10 | 134414342401100 |
11 | 39912891124443 |
12 | 130aa4973824b8 |
13 | 5a002ab223308 |
14 | 2529990427416 |
15 | 108165b167835 |
hex | 7a3fc721ac4c |
134414342401100 has 36 divisors (see below), whose sum is σ = 291816126348600. Its totient is φ = 53740482888960.
The previous prime is 134414342401099. The next prime is 134414342401151. The reversal of 134414342401100 is 1104243414431.
It is a super-3 number, since 3×1344143424011003 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 315461930 + ... + 315887729.
Almost surely, 2134414342401100 is an apocalyptic number.
134414342401100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
134414342401100 is an abundant number, since it is smaller than the sum of its proper divisors (157401783947500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134414342401100 is a wasteful number, since it uses less digits than its factorization.
134414342401100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 631351802 (or 631351795 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 134414342401100 its reverse (1104243414431), we get a palindrome (135518585815531).
The spelling of 134414342401100 in words is "one hundred thirty-four trillion, four hundred fourteen billion, three hundred forty-two million, four hundred one thousand, one hundred".
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