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1344161153344 = 2621002518021
BaseRepresentation
bin10011100011110110001…
…111111000000101000000
311202111111220100111000011
4103203312033320011000
5134010320223401334
62505255450234304
7166053365200522
oct23436617700500
94674456314004
101344161153344
11479067a24339
12198610a25994
13999a52a3ac9
14490b4659a12
1524e70db6564
hex138f63f8140

1344161153344 has 14 divisors (see below), whose sum is σ = 2667319788794. Its totient is φ = 672080576640.

The previous prime is 1344161153333. The next prime is 1344161153381. The reversal of 1344161153344 is 4433511614431.

It can be written as a sum of positive squares in only one way, i.e., 1178440513600 + 165720639744 = 1085560^2 + 407088^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1344161153297 and 1344161153306.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10501258947 + ... + 10501259074.

Almost surely, 21344161153344 is an apocalyptic number.

It is an amenable number.

1344161153344 is a deficient number, since it is larger than the sum of its proper divisors (1323158635450).

1344161153344 is an equidigital number, since it uses as much as digits as its factorization.

1344161153344 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21002518033 (or 21002518023 counting only the distinct ones).

The product of its digits is 207360, while the sum is 40.

Adding to 1344161153344 its reverse (4433511614431), we get a palindrome (5777672767775).

The spelling of 1344161153344 in words is "one trillion, three hundred forty-four billion, one hundred sixty-one million, one hundred fifty-three thousand, three hundred forty-four".

Divisors: 1 2 4 8 16 32 64 21002518021 42005036042 84010072084 168020144168 336040288336 672080576672 1344161153344