Base | Representation |
---|---|
bin | 10011100011110110001… |
… | …111111000000101000000 |
3 | 11202111111220100111000011 |
4 | 103203312033320011000 |
5 | 134010320223401334 |
6 | 2505255450234304 |
7 | 166053365200522 |
oct | 23436617700500 |
9 | 4674456314004 |
10 | 1344161153344 |
11 | 479067a24339 |
12 | 198610a25994 |
13 | 999a52a3ac9 |
14 | 490b4659a12 |
15 | 24e70db6564 |
hex | 138f63f8140 |
1344161153344 has 14 divisors (see below), whose sum is σ = 2667319788794. Its totient is φ = 672080576640.
The previous prime is 1344161153333. The next prime is 1344161153381. The reversal of 1344161153344 is 4433511614431.
It can be written as a sum of positive squares in only one way, i.e., 1178440513600 + 165720639744 = 1085560^2 + 407088^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1344161153297 and 1344161153306.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10501258947 + ... + 10501259074.
Almost surely, 21344161153344 is an apocalyptic number.
It is an amenable number.
1344161153344 is a deficient number, since it is larger than the sum of its proper divisors (1323158635450).
1344161153344 is an equidigital number, since it uses as much as digits as its factorization.
1344161153344 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21002518033 (or 21002518023 counting only the distinct ones).
The product of its digits is 207360, while the sum is 40.
Adding to 1344161153344 its reverse (4433511614431), we get a palindrome (5777672767775).
The spelling of 1344161153344 in words is "one trillion, three hundred forty-four billion, one hundred sixty-one million, one hundred fifty-three thousand, three hundred forty-four".
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