13442251451 has 2 divisors, whose sum is σ = 13442251452. Its totient is φ = 13442251450.

The previous prime is 13442251447. The next prime is 13442251453. The reversal of 13442251451 is 15415224431.

It is a strong prime.

It is an emirp because it is prime and its reverse (15415224431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13442251451 - 2² = 13442251447 is a prime.

Together with 13442251453, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13442251453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721125725 + 6721125726.

It is an arithmetic number, because the mean of its divisors is an integer number (6721125726).

Almost surely, 2^13442251451 is an apocalyptic number.

13442251451 is a deficient number, since it is larger than the sum of its proper divisors (1).

13442251451 is an equidigital number, since it uses as much as digits as its factorization.

13442251451 is an evil number, because the sum of its binary digits is even.

The product of its digits is 19200, while the sum is 32.

Adding to 13442251451 its reverse (15415224431), we get a palindrome (28857475882).

The spelling of 13442251451 in words is "thirteen billion, four hundred forty-two million, two hundred fifty-one thousand, four hundred fifty-one".