Base | Representation |
---|---|
bin | 10011100011111010010… |
… | …110100101100110011111 |
3 | 11202111200200221100101220 |
4 | 103203322112211212133 |
5 | 134010440341142120 |
6 | 2505310350304423 |
7 | 166055162441442 |
oct | 23437226454637 |
9 | 4674620840356 |
10 | 1344230021535 |
11 | 4790a2891aa5 |
12 | 19862bab8113 |
13 | 999b663740b |
14 | 490bd865659 |
15 | 24e76e6bb40 |
hex | 138fa5a599f |
1344230021535 has 32 divisors (see below), whose sum is σ = 2286624619008. Its totient is φ = 672813398400.
The previous prime is 1344230021509. The next prime is 1344230021539. The reversal of 1344230021535 is 5351200324431.
It is not a de Polignac number, because 1344230021535 - 25 = 1344230021503 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1344230021496 and 1344230021505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1344230021539) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 36739441 + ... + 36776010.
It is an arithmetic number, because the mean of its divisors is an integer number (71457019344).
Almost surely, 21344230021535 is an apocalyptic number.
1344230021535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1344230021535 is a deficient number, since it is larger than the sum of its proper divisors (942394597473).
1344230021535 is a wasteful number, since it uses less digits than its factorization.
1344230021535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73515535.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 1344230021535 its reverse (5351200324431), we get a palindrome (6695430345966).
The spelling of 1344230021535 in words is "one trillion, three hundred forty-four billion, two hundred thirty million, twenty-one thousand, five hundred thirty-five".
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