1344240160031 has 2 divisors, whose sum is σ = 1344240160032. Its totient is φ = 1344240160030.

The previous prime is 1344240160019. The next prime is 1344240160037. The reversal of 1344240160031 is 1300610424431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1344240160031 - 2³⁸ = 1069362253087 is a prime.

It is a super-2 number, since 2×1344240160031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1344240159976 and 1344240160003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1344240160037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672120080015 + 672120080016.

It is an arithmetic number, because the mean of its divisors is an integer number (672120080016).

Almost surely, 2^{1344240160031} is an apocalyptic number.

1344240160031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344240160031 is an equidigital number, since it uses as much as digits as its factorization.

1344240160031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1344240160031 its reverse (1300610424431), we get a palindrome (2644850584462).

The spelling of 1344240160031 in words is "one trillion, three hundred forty-four billion, two hundred forty million, one hundred sixty thousand, thirty-one".