Base | Representation |
---|---|
bin | 111110100110001010… |
… | …0001011100111000111 |
3 | 110211222021010021000121 |
4 | 1331030110023213013 |
5 | 4200300113020111 |
6 | 141430444122411 |
7 | 12466106036314 |
oct | 1751424134707 |
9 | 424867107017 |
10 | 134424345031 |
11 | 52011047029 |
12 | 22076536407 |
13 | c8a36ac882 |
14 | 6712d1dd0b |
15 | 376b4aa871 |
hex | 1f4c50b9c7 |
134424345031 has 2 divisors, whose sum is σ = 134424345032. Its totient is φ = 134424345030.
The previous prime is 134424344993. The next prime is 134424345049. The reversal of 134424345031 is 130543424431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134424345031 is a prime.
It is a super-2 number, since 2×1344243450312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134424345071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67212172515 + 67212172516.
It is an arithmetic number, because the mean of its divisors is an integer number (67212172516).
Almost surely, 2134424345031 is an apocalyptic number.
134424345031 is a deficient number, since it is larger than the sum of its proper divisors (1).
134424345031 is an equidigital number, since it uses as much as digits as its factorization.
134424345031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 134424345031 its reverse (130543424431), we get a palindrome (264967769462).
The spelling of 134424345031 in words is "one hundred thirty-four billion, four hundred twenty-four million, three hundred forty-five thousand, thirty-one".
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