Base | Representation |
---|---|
bin | 11001000010100011… |
… | …00001100101100101 |
3 | 1021200212122110210121 |
4 | 30201101201211211 |
5 | 210012421102122 |
6 | 10101541121541 |
7 | 654063560521 |
oct | 144121414545 |
9 | 37625573717 |
10 | 13443144037 |
11 | 57793390a4 |
12 | 27320b92b1 |
13 | 136313abcb |
14 | 917560d81 |
15 | 53a2d8bc7 |
hex | 321461965 |
13443144037 has 2 divisors, whose sum is σ = 13443144038. Its totient is φ = 13443144036.
The previous prime is 13443143999. The next prime is 13443144049. The reversal of 13443144037 is 73044134431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11471695236 + 1971448801 = 107106^2 + 44401^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13443144037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13443143993 and 13443144011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13443147037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721572018 + 6721572019.
It is an arithmetic number, because the mean of its divisors is an integer number (6721572019).
Almost surely, 213443144037 is an apocalyptic number.
It is an amenable number.
13443144037 is a deficient number, since it is larger than the sum of its proper divisors (1).
13443144037 is an equidigital number, since it uses as much as digits as its factorization.
13443144037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 34.
Adding to 13443144037 its reverse (73044134431), we get a palindrome (86487278468).
The spelling of 13443144037 in words is "thirteen billion, four hundred forty-three million, one hundred forty-four thousand, thirty-seven".
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