Base | Representation |
---|---|
bin | 111110100110101000… |
… | …0010010010111011111 |
3 | 110212000100202202121201 |
4 | 1331031100102113133 |
5 | 4200313131220333 |
6 | 141432205540331 |
7 | 12466360002142 |
oct | 1751520222737 |
9 | 425010682551 |
10 | 134440101343 |
11 | 52019a28a79 |
12 | 2207b8746a7 |
13 | c8a6a38532 |
14 | 6715062059 |
15 | 376ca6e17d |
hex | 1f4d4125df |
134440101343 has 2 divisors, whose sum is σ = 134440101344. Its totient is φ = 134440101342.
The previous prime is 134440101329. The next prime is 134440101373. The reversal of 134440101343 is 343101044431.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (343101044431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134440101343 - 25 = 134440101311 is a prime.
It is a super-2 number, since 2×1344401013432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134440101373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67220050671 + 67220050672.
It is an arithmetic number, because the mean of its divisors is an integer number (67220050672).
Almost surely, 2134440101343 is an apocalyptic number.
134440101343 is a deficient number, since it is larger than the sum of its proper divisors (1).
134440101343 is an equidigital number, since it uses as much as digits as its factorization.
134440101343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 134440101343 its reverse (343101044431), we get a palindrome (477541145774).
The spelling of 134440101343 in words is "one hundred thirty-four billion, four hundred forty million, one hundred one thousand, three hundred forty-three".
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