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134440101343 is a prime number
BaseRepresentation
bin111110100110101000…
…0010010010111011111
3110212000100202202121201
41331031100102113133
54200313131220333
6141432205540331
712466360002142
oct1751520222737
9425010682551
10134440101343
1152019a28a79
122207b8746a7
13c8a6a38532
146715062059
15376ca6e17d
hex1f4d4125df

134440101343 has 2 divisors, whose sum is σ = 134440101344. Its totient is φ = 134440101342.

The previous prime is 134440101329. The next prime is 134440101373. The reversal of 134440101343 is 343101044431.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (343101044431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134440101343 - 25 = 134440101311 is a prime.

It is a super-2 number, since 2×1344401013432 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134440101373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67220050671 + 67220050672.

It is an arithmetic number, because the mean of its divisors is an integer number (67220050672).

Almost surely, 2134440101343 is an apocalyptic number.

134440101343 is a deficient number, since it is larger than the sum of its proper divisors (1).

134440101343 is an equidigital number, since it uses as much as digits as its factorization.

134440101343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 134440101343 its reverse (343101044431), we get a palindrome (477541145774).

The spelling of 134440101343 in words is "one hundred thirty-four billion, four hundred forty million, one hundred one thousand, three hundred forty-three".