Base | Representation |
---|---|
bin | 11110100100010111010010… |
… | …011100111001000011000111 |
3 | 122122000100220210211020111211 |
4 | 132210113102130321003013 |
5 | 120110132214320334114 |
6 | 1153533004442312251 |
7 | 40213664005042246 |
oct | 3644272234710307 |
9 | 578010823736454 |
10 | 134440302121159 |
11 | 399228a2772341 |
12 | 130b35211b8687 |
13 | 5a02887532908 |
14 | 252ad3403495d |
15 | 108217a2116c4 |
hex | 7a45d27390c7 |
134440302121159 has 2 divisors, whose sum is σ = 134440302121160. Its totient is φ = 134440302121158.
The previous prime is 134440302121157. The next prime is 134440302121249. The reversal of 134440302121159 is 951121203044431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134440302121159 - 21 = 134440302121157 is a prime.
It is a super-2 number, since 2×1344403021211592 (a number of 29 digits) contains 22 as substring.
Together with 134440302121157, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134440302121157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67220151060579 + 67220151060580.
It is an arithmetic number, because the mean of its divisors is an integer number (67220151060580).
Almost surely, 2134440302121159 is an apocalyptic number.
134440302121159 is a deficient number, since it is larger than the sum of its proper divisors (1).
134440302121159 is an equidigital number, since it uses as much as digits as its factorization.
134440302121159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 40.
The spelling of 134440302121159 in words is "one hundred thirty-four trillion, four hundred forty billion, three hundred two million, one hundred twenty-one thousand, one hundred fifty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •