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1344422113 is a prime number
BaseRepresentation
bin101000000100010…
…0100000011100001
310110200202201102121
41100020210003201
510223133001423
6341223344241
745213253666
oct12010440341
93420681377
101344422113
1162a989261
123162b2081
131856bc558
14ca7a5a6d
157d06745d
hex502240e1

1344422113 has 2 divisors, whose sum is σ = 1344422114. Its totient is φ = 1344422112.

The previous prime is 1344422111. The next prime is 1344422141. The reversal of 1344422113 is 3112244431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1142980864 + 201441249 = 33808^2 + 14193^2 .

It is a cyclic number.

It is not a de Polignac number, because 1344422113 - 21 = 1344422111 is a prime.

Together with 1344422111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1344422111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672211056 + 672211057.

It is an arithmetic number, because the mean of its divisors is an integer number (672211057).

Almost surely, 21344422113 is an apocalyptic number.

It is an amenable number.

1344422113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344422113 is an equidigital number, since it uses as much as digits as its factorization.

1344422113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2304, while the sum is 25.

The square root of 1344422113 is about 36666.3621457052. The cubic root of 1344422113 is about 1103.6851919673.

Adding to 1344422113 its reverse (3112244431), we get a palindrome (4456666544).

The spelling of 1344422113 in words is "one billion, three hundred forty-four million, four hundred twenty-two thousand, one hundred thirteen".