Base | Representation |
---|---|
bin | 1100001110100100111011… |
… | …0001000100111101001111 |
3 | 1202121021210010202000112001 |
4 | 3003221032301010331033 |
5 | 3230233434143442222 |
6 | 44332203315453131 |
7 | 2555223645663421 |
oct | 303511661047517 |
9 | 52537703660461 |
10 | 13444569124687 |
11 | 431389a854138 |
12 | 1611792bb71a7 |
13 | 766a81b75a8c |
14 | 346a13536811 |
15 | 184acdc5be27 |
hex | c3a4ec44f4f |
13444569124687 has 2 divisors, whose sum is σ = 13444569124688. Its totient is φ = 13444569124686.
The previous prime is 13444569124639. The next prime is 13444569124703. The reversal of 13444569124687 is 78642196544431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13444569124687 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13444569164687) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722284562343 + 6722284562344.
It is an arithmetic number, because the mean of its divisors is an integer number (6722284562344).
Almost surely, 213444569124687 is an apocalyptic number.
13444569124687 is a deficient number, since it is larger than the sum of its proper divisors (1).
13444569124687 is an equidigital number, since it uses as much as digits as its factorization.
13444569124687 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 139345920, while the sum is 64.
The spelling of 13444569124687 in words is "thirteen trillion, four hundred forty-four billion, five hundred sixty-nine million, one hundred twenty-four thousand, six hundred eighty-seven".
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