Base | Representation |
---|---|
bin | 1100001110101000011100… |
… | …0010100110001000100101 |
3 | 1202121101012221021002210112 |
4 | 3003222013002212020211 |
5 | 3230242402342204000 |
6 | 44332441123302405 |
7 | 2555256231563450 |
oct | 303520702461045 |
9 | 52541187232715 |
10 | 13445513241125 |
11 | 4314234778859 |
12 | 16119b721aa05 |
13 | 766ba2647864 |
14 | 346aa2a98497 |
15 | 184b36aa0235 |
hex | c3a870a6225 |
13445513241125 has 64 divisors (see below), whose sum is σ = 19846357240320. Its totient is φ = 8898297408000.
The previous prime is 13445513241109. The next prime is 13445513241191. The reversal of 13445513241125 is 52114231554431.
It is not a de Polignac number, because 13445513241125 - 24 = 13445513241109 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 64119449 + ... + 64328801.
It is an arithmetic number, because the mean of its divisors is an integer number (310099331880).
Almost surely, 213445513241125 is an apocalyptic number.
It is an amenable number.
13445513241125 is a deficient number, since it is larger than the sum of its proper divisors (6400843999195).
13445513241125 is a wasteful number, since it uses less digits than its factorization.
13445513241125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211935 (or 211925 counting only the distinct ones).
The product of its digits is 288000, while the sum is 41.
Adding to 13445513241125 its reverse (52114231554431), we get a palindrome (65559744795556).
The spelling of 13445513241125 in words is "thirteen trillion, four hundred forty-five billion, five hundred thirteen million, two hundred forty-one thousand, one hundred twenty-five".
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