Base | Representation |
---|---|
bin | 10011100100001101110… |
… | …000011010000000100101 |
3 | 11202112112101111020222022 |
4 | 103210031300122000211 |
5 | 134012122210310101 |
6 | 2505402535512525 |
7 | 166066224443234 |
oct | 23441560320045 |
9 | 4675471436868 |
10 | 1344555556901 |
11 | 47924a617597 |
12 | 198700b28745 |
13 | 99a38c05cab |
14 | 49110ba4b1b |
15 | 24e95821a1b |
hex | 1390dc1a025 |
1344555556901 has 2 divisors, whose sum is σ = 1344555556902. Its totient is φ = 1344555556900.
The previous prime is 1344555556889. The next prime is 1344555556907. The reversal of 1344555556901 is 1096555554431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1310681522500 + 33874034401 = 1144850^2 + 184049^2 .
It is a cyclic number.
It is not a de Polignac number, because 1344555556901 - 234 = 1327375687717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344555556907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672277778450 + 672277778451.
It is an arithmetic number, because the mean of its divisors is an integer number (672277778451).
Almost surely, 21344555556901 is an apocalyptic number.
It is an amenable number.
1344555556901 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344555556901 is an equidigital number, since it uses as much as digits as its factorization.
1344555556901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100000, while the sum is 53.
The spelling of 1344555556901 in words is "one trillion, three hundred forty-four billion, five hundred fifty-five million, five hundred fifty-six thousand, nine hundred one".
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