1344829607650 has 24 divisors (see below), whose sum is σ = 2507159976804. Its totient is φ = 536689497600.

The previous prime is 1344829607647. The next prime is 1344829607683. The reversal of 1344829607650 is 567069284431.

It can be written as a sum of positive squares in 6 ways, for example, as 231388898841 + 1113440708809 = 481029^2 + 1055197^2 .

It is a super-2 number, since 2×1344829607650² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1344829607591 and 1344829607600.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 31036771 + ... + 31080070.

It is a 1-persistent number, because it is pandigital, but 2⋅1344829607650 = 2689659215300 is not.

Almost surely, 2^{1344829607650} is an apocalyptic number.

1344829607650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1344829607650 is a deficient number, since it is larger than the sum of its proper divisors (1162330369154).

1344829607650 is a wasteful number, since it uses less digits than its factorization.

1344829607650 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62117286 (or 62117281 counting only the distinct ones).

The product of its (nonzero) digits is 8709120, while the sum is 55.

The spelling of 1344829607650 in words is "one trillion, three hundred forty-four billion, eight hundred twenty-nine million, six hundred seven thousand, six hundred fifty".