Base | Representation |
---|---|
bin | 10011100100011111011… |
… | …011100001110110110011 |
3 | 11202120022001102212211122 |
4 | 103210133123201312303 |
5 | 134013224112331112 |
6 | 2505452211132455 |
7 | 166106455005266 |
oct | 23443733416663 |
9 | 4676261385748 |
10 | 1344852073907 |
11 | 479391a32171 |
12 | 1987842a412b |
13 | 99a85484644 |
14 | 4913c30ccdd |
15 | 24eb1893872 |
hex | 1391f6e1db3 |
1344852073907 has 2 divisors, whose sum is σ = 1344852073908. Its totient is φ = 1344852073906.
The previous prime is 1344852073861. The next prime is 1344852073909. The reversal of 1344852073907 is 7093702584431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1344852073907 - 28 = 1344852073651 is a prime.
Together with 1344852073909, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1344852073909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672426036953 + 672426036954.
It is an arithmetic number, because the mean of its divisors is an integer number (672426036954).
Almost surely, 21344852073907 is an apocalyptic number.
1344852073907 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344852073907 is an equidigital number, since it uses as much as digits as its factorization.
1344852073907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5080320, while the sum is 53.
The spelling of 1344852073907 in words is "one trillion, three hundred forty-four billion, eight hundred fifty-two million, seventy-three thousand, nine hundred seven".
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