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1344991156849 is a prime number
BaseRepresentation
bin10011100100100111101…
…110000101101001110001
311202120122202011000202201
4103210213232011221301
5134014020214004344
62505514100143201
7166113064126024
oct23444756055161
94676582130681
101344991156849
1147945349824a
12198802997b01
1399aa8230442
14491529951bb
1524ebdbb84d4
hex13927b85a71

1344991156849 has 2 divisors, whose sum is σ = 1344991156850. Its totient is φ = 1344991156848.

The previous prime is 1344991156819. The next prime is 1344991156879. The reversal of 1344991156849 is 9486511994431.

It is a balanced prime because it is at equal distance from previous prime (1344991156819) and next prime (1344991156879).

It can be written as a sum of positive squares in only one way, i.e., 1135062244449 + 209928912400 = 1065393^2 + 458180^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1344991156849 is a prime.

It is a super-2 number, since 2×13449911568492 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1344991156819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672495578424 + 672495578425.

It is an arithmetic number, because the mean of its divisors is an integer number (672495578425).

Almost surely, 21344991156849 is an apocalyptic number.

It is an amenable number.

1344991156849 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344991156849 is an equidigital number, since it uses as much as digits as its factorization.

1344991156849 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 33592320, while the sum is 64.

The spelling of 1344991156849 in words is "one trillion, three hundred forty-four billion, nine hundred ninety-one million, one hundred fifty-six thousand, eight hundred forty-nine".