Base | Representation |
---|---|
bin | 111110101000011010… |
… | …1001101100010101101 |
3 | 110212011112200122112021 |
4 | 1331100311031202231 |
5 | 4200424012100212 |
6 | 141442152110141 |
7 | 12501016044016 |
oct | 1752065154255 |
9 | 425145618467 |
10 | 134500112557 |
11 | 5204a897318 |
12 | 22097995351 |
13 | c8b62ba625 |
14 | 671d00400d |
15 | 3772e75307 |
hex | 1f50d4d8ad |
134500112557 has 2 divisors, whose sum is σ = 134500112558. Its totient is φ = 134500112556.
The previous prime is 134500112441. The next prime is 134500112587. The reversal of 134500112557 is 755211005431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105524923716 + 28975188841 = 324846^2 + 170221^2 .
It is an emirp because it is prime and its reverse (755211005431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134500112557 - 211 = 134500110509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134500112587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67250056278 + 67250056279.
It is an arithmetic number, because the mean of its divisors is an integer number (67250056279).
Almost surely, 2134500112557 is an apocalyptic number.
It is an amenable number.
134500112557 is a deficient number, since it is larger than the sum of its proper divisors (1).
134500112557 is an equidigital number, since it uses as much as digits as its factorization.
134500112557 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21000, while the sum is 34.
Adding to 134500112557 its reverse (755211005431), we get a palindrome (889711117988).
The spelling of 134500112557 in words is "one hundred thirty-four billion, five hundred million, one hundred twelve thousand, five hundred fifty-seven".
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