Base | Representation |
---|---|
bin | 10011100100101011111… |
… | …110011100111100001111 |
3 | 11202120211201111110011202 |
4 | 103210223332130330033 |
5 | 134014142003233112 |
6 | 2505525130340115 |
7 | 166114622036054 |
oct | 23445376347417 |
9 | 4676751443152 |
10 | 1345062555407 |
11 | 47948a82401a |
12 | 19882288a63b |
13 | 99ab9c6b6cc |
14 | 4915c25d02b |
15 | 24ec50bd6c2 |
hex | 1392bf9cf0f |
1345062555407 has 2 divisors, whose sum is σ = 1345062555408. Its totient is φ = 1345062555406.
The previous prime is 1345062555401. The next prime is 1345062555437. The reversal of 1345062555407 is 7045552605431.
It is a weak prime.
It is an emirp because it is prime and its reverse (7045552605431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1345062555407 - 210 = 1345062554383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1345062555401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672531277703 + 672531277704.
It is an arithmetic number, because the mean of its divisors is an integer number (672531277704).
Almost surely, 21345062555407 is an apocalyptic number.
1345062555407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1345062555407 is an equidigital number, since it uses as much as digits as its factorization.
1345062555407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2520000, while the sum is 47.
The spelling of 1345062555407 in words is "one trillion, three hundred forty-five billion, sixty-two million, five hundred fifty-five thousand, four hundred seven".
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