13451243471 has 2 divisors, whose sum is σ = 13451243472. Its totient is φ = 13451243470.

The previous prime is 13451243441. The next prime is 13451243473. The reversal of 13451243471 is 17434215431.

It is a strong prime.

It is an emirp because it is prime and its reverse (17434215431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13451243471 is a prime.

It is a super-3 number, since 3×13451243471³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13451243473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13451243473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6725621735 + 6725621736.

It is an arithmetic number, because the mean of its divisors is an integer number (6725621736).

Almost surely, 2^13451243471 is an apocalyptic number.

13451243471 is a deficient number, since it is larger than the sum of its proper divisors (1).

13451243471 is an equidigital number, since it uses as much as digits as its factorization.

13451243471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 40320, while the sum is 35.

The spelling of 13451243471 in words is "thirteen billion, four hundred fifty-one million, two hundred forty-three thousand, four hundred seventy-one".