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1345240414127 is a prime number
BaseRepresentation
bin10011100100110110100…
…100111011011110101111
311202121022010011121110202
4103210312210323132233
5134020023021223002
62505554522424115
7166122211565441
oct23446644733657
94677263147422
101345240414127
114795711639a5
1219887236203b
1399b17a72a5c
1449177b1a491
1524ed5a02502
hex1393693b7af

1345240414127 has 2 divisors, whose sum is σ = 1345240414128. Its totient is φ = 1345240414126.

The previous prime is 1345240413991. The next prime is 1345240414211. The reversal of 1345240414127 is 7214140425431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1345240414127 - 228 = 1344971978671 is a prime.

It is a super-3 number, since 3×13452404141273 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1345240414327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672620207063 + 672620207064.

It is an arithmetic number, because the mean of its divisors is an integer number (672620207064).

Almost surely, 21345240414127 is an apocalyptic number.

1345240414127 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345240414127 is an equidigital number, since it uses as much as digits as its factorization.

1345240414127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 107520, while the sum is 38.

Adding to 1345240414127 its reverse (7214140425431), we get a palindrome (8559380839558).

The spelling of 1345240414127 in words is "one trillion, three hundred forty-five billion, two hundred forty million, four hundred fourteen thousand, one hundred twenty-seven".