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1345242025343 is a prime number
BaseRepresentation
bin10011100100110110101…
…011000100110101111111
311202121022020012110122102
4103210312223010311333
5134020023424302333
62505555021135315
7166122231356036
oct23446653046577
94677266173572
101345242025343
11479572064487
121988729ba53b
1399b181b8238
144917801971d
1524ed5c1eae8
hex13936ac4d7f

1345242025343 has 2 divisors, whose sum is σ = 1345242025344. Its totient is φ = 1345242025342.

The previous prime is 1345242025291. The next prime is 1345242025367. The reversal of 1345242025343 is 3435202425431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1345242025343 - 220 = 1345240976767 is a prime.

It is a super-2 number, since 2×13452420253432 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 1345242025297 and 1345242025306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1345242015343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672621012671 + 672621012672.

It is an arithmetic number, because the mean of its divisors is an integer number (672621012672).

Almost surely, 21345242025343 is an apocalyptic number.

1345242025343 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345242025343 is an equidigital number, since it uses as much as digits as its factorization.

1345242025343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 38.

The spelling of 1345242025343 in words is "one trillion, three hundred forty-five billion, two hundred forty-two million, twenty-five thousand, three hundred forty-three".