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134525525501 is a prime number
BaseRepresentation
bin111110101001001011…
…0001001110111111101
3110212020022111202112102
41331102112021313331
54201002013304001
6141444500514445
712501445046153
oct1752226116775
9425208452472
10134525525501
1152063174454
12220a43aba25
13c8bb647783
14672253b3d3
1537752e4e6b
hex1f52589dfd

134525525501 has 2 divisors, whose sum is σ = 134525525502. Its totient is φ = 134525525500.

The previous prime is 134525525419. The next prime is 134525525513. The reversal of 134525525501 is 105525525431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82802940025 + 51722585476 = 287755^2 + 227426^2 .

It is an emirp because it is prime and its reverse (105525525431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134525525501 is a prime.

It is a super-2 number, since 2×1345255255012 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134525525581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67262762750 + 67262762751.

It is an arithmetic number, because the mean of its divisors is an integer number (67262762751).

Almost surely, 2134525525501 is an apocalyptic number.

It is an amenable number.

134525525501 is a deficient number, since it is larger than the sum of its proper divisors (1).

134525525501 is an equidigital number, since it uses as much as digits as its factorization.

134525525501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 150000, while the sum is 38.

The spelling of 134525525501 in words is "one hundred thirty-four billion, five hundred twenty-five million, five hundred twenty-five thousand, five hundred one".