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13452625471 is a prime number
BaseRepresentation
bin11001000011101011…
…01100011000111111
31021201112111011212211
430201311230120333
5210022333003341
610102520241251
7654240300265
oct144165543077
937645434784
1013452625471
11578372469a
122735310227
1313650aa71c
1491890c435
1553b05d181
hex321d6c63f

13452625471 has 2 divisors, whose sum is σ = 13452625472. Its totient is φ = 13452625470.

The previous prime is 13452625469. The next prime is 13452625477. The reversal of 13452625471 is 17452625431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13452625471 - 21 = 13452625469 is a prime.

It is a super-3 number, since 3×134526254713 (a number of 31 digits) contains 333 as substring.

Together with 13452625469, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13452625477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6726312735 + 6726312736.

It is an arithmetic number, because the mean of its divisors is an integer number (6726312736).

Almost surely, 213452625471 is an apocalyptic number.

13452625471 is a deficient number, since it is larger than the sum of its proper divisors (1).

13452625471 is an equidigital number, since it uses as much as digits as its factorization.

13452625471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 201600, while the sum is 40.

Subtracting from 13452625471 its sum of digits (40), we obtain a palindrome (13452625431).

The spelling of 13452625471 in words is "thirteen billion, four hundred fifty-two million, six hundred twenty-five thousand, four hundred seventy-one".