Base | Representation |
---|---|
bin | 10011100100111010110… |
… | …011011110100001011011 |
3 | 11202121111001121211201202 |
4 | 103210322303132201123 |
5 | 134020144200232124 |
6 | 2510005534504415 |
7 | 166124032453352 |
oct | 23447263364133 |
9 | 4677431554652 |
10 | 1345311336539 |
11 | 4795a81a4a65 |
12 | 19889206510b |
13 | 99b29675391 |
14 | 491832dc999 |
15 | 24edbd615ae |
hex | 1393acde85b |
1345311336539 has 2 divisors, whose sum is σ = 1345311336540. Its totient is φ = 1345311336538.
The previous prime is 1345311336533. The next prime is 1345311336557. The reversal of 1345311336539 is 9356331135431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1345311336539 - 28 = 1345311336283 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1345311336493 and 1345311336502.
It is not a weakly prime, because it can be changed into another prime (1345311336533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672655668269 + 672655668270.
It is an arithmetic number, because the mean of its divisors is an integer number (672655668270).
Almost surely, 21345311336539 is an apocalyptic number.
1345311336539 is a deficient number, since it is larger than the sum of its proper divisors (1).
1345311336539 is an equidigital number, since it uses as much as digits as its factorization.
1345311336539 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1312200, while the sum is 47.
The spelling of 1345311336539 in words is "one trillion, three hundred forty-five billion, three hundred eleven million, three hundred thirty-six thousand, five hundred thirty-nine".
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