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1345311336557 is a prime number
BaseRepresentation
bin10011100100111010110…
…011011110100001101101
311202121111001121211202102
4103210322303132201231
5134020144200232212
62510005534504445
7166124032453406
oct23447263364155
94677431554672
101345311336557
114795a81a4a81
12198892065125
1399b296753a6
14491832dc9ad
1524edbd615c2
hex1393acde86d

1345311336557 has 2 divisors, whose sum is σ = 1345311336558. Its totient is φ = 1345311336556.

The previous prime is 1345311336539. The next prime is 1345311336569. The reversal of 1345311336557 is 7556331135431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 813723068356 + 531588268201 = 902066^2 + 729101^2 .

It is a cyclic number.

It is not a de Polignac number, because 1345311336557 - 216 = 1345311271021 is a prime.

It is a super-2 number, since 2×13453113365572 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1345311336157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672655668278 + 672655668279.

It is an arithmetic number, because the mean of its divisors is an integer number (672655668279).

Almost surely, 21345311336557 is an apocalyptic number.

It is an amenable number.

1345311336557 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345311336557 is an equidigital number, since it uses as much as digits as its factorization.

1345311336557 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1701000, while the sum is 47.

The spelling of 1345311336557 in words is "one trillion, three hundred forty-five billion, three hundred eleven million, three hundred thirty-six thousand, five hundred fifty-seven".