Base | Representation |
---|---|
bin | 111110101001101011… |
… | …0010100001101000111 |
3 | 110212021111011021120222 |
4 | 1331103112110031013 |
5 | 4201020320020111 |
6 | 141450301214555 |
7 | 12502041030533 |
oct | 1752326241507 |
9 | 425244137528 |
10 | 134542345031 |
11 | 52071712196 |
12 | 220a9b6145b |
13 | c8c1c86363 |
14 | 6724878bc3 |
15 | 3776a187db |
hex | 1f53594347 |
134542345031 has 2 divisors, whose sum is σ = 134542345032. Its totient is φ = 134542345030.
The previous prime is 134542344997. The next prime is 134542345033. The reversal of 134542345031 is 130543245431.
It is a strong prime.
It is an emirp because it is prime and its reverse (130543245431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134542345031 - 210 = 134542344007 is a prime.
It is a super-2 number, since 2×1345423450312 (a number of 23 digits) contains 22 as substring.
Together with 134542345033, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 134542344982 and 134542345000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134542345033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67271172515 + 67271172516.
It is an arithmetic number, because the mean of its divisors is an integer number (67271172516).
Almost surely, 2134542345031 is an apocalyptic number.
134542345031 is a deficient number, since it is larger than the sum of its proper divisors (1).
134542345031 is an equidigital number, since it uses as much as digits as its factorization.
134542345031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
The spelling of 134542345031 in words is "one hundred thirty-four billion, five hundred forty-two million, three hundred forty-five thousand, thirty-one".
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