1345440231137 has 2 divisors, whose sum is σ = 1345440231138. Its totient is φ = 1345440231136.

The previous prime is 1345440231133. The next prime is 1345440231139. The reversal of 1345440231137 is 7311320445431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1343649587281 + 1790643856 = 1159159^2 + 42316^2 .

It is a cyclic number.

It is not a de Polignac number, because 1345440231137 - 2² = 1345440231133 is a prime.

Together with 1345440231139, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1345440231137.

It is not a weakly prime, because it can be changed into another prime (1345440231133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672720115568 + 672720115569.

It is an arithmetic number, because the mean of its divisors is an integer number (672720115569).

Almost surely, 2^{1345440231137} is an apocalyptic number.

It is an amenable number.

1345440231137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345440231137 is an equidigital number, since it uses as much as digits as its factorization.

1345440231137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 38.

Adding to 1345440231137 its reverse (7311320445431), we get a palindrome (8656760676568).

The spelling of 1345440231137 in words is "one trillion, three hundred forty-five billion, four hundred forty million, two hundred thirty-one thousand, one hundred thirty-seven".