Base | Representation |
---|---|
bin | 111110101001110001… |
… | …0100000110100011111 |
3 | 110212021201011201121012 |
4 | 1331103202200310133 |
5 | 4201022124324211 |
6 | 141450453525435 |
7 | 12502110145436 |
oct | 1752342406437 |
9 | 425251151535 |
10 | 134545542431 |
11 | 520734a6473 |
12 | 220ab04387b |
13 | c8c2835801 |
14 | 672506c11d |
15 | 3776e4ad8b |
hex | 1f538a0d1f |
134545542431 has 2 divisors, whose sum is σ = 134545542432. Its totient is φ = 134545542430.
The previous prime is 134545542413. The next prime is 134545542449. The reversal of 134545542431 is 134245545431.
Together with previous prime (134545542413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a balanced prime because it is at equal distance from previous prime (134545542413) and next prime (134545542449).
It is a cyclic number.
It is not a de Polignac number, because 134545542431 - 210 = 134545541407 is a prime.
It is a super-2 number, since 2×1345455424312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134545544431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67272771215 + 67272771216.
It is an arithmetic number, because the mean of its divisors is an integer number (67272771216).
Almost surely, 2134545542431 is an apocalyptic number.
134545542431 is a deficient number, since it is larger than the sum of its proper divisors (1).
134545542431 is an equidigital number, since it uses as much as digits as its factorization.
134545542431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576000, while the sum is 41.
The spelling of 134545542431 in words is "one hundred thirty-four billion, five hundred forty-five million, five hundred forty-two thousand, four hundred thirty-one".
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