Base | Representation |
---|---|
bin | 10011100101000111101… |
… | …110100110000110001011 |
3 | 11202122001011121122111102 |
4 | 103211013232212012023 |
5 | 134021120202120101 |
6 | 2510043242052015 |
7 | 166132304441543 |
oct | 23450756460613 |
9 | 4678034548442 |
10 | 1345528160651 |
11 | 4796a9629144 |
12 | 1989327aa00b |
13 | 99b6257037c |
14 | 491a4020323 |
15 | 25000de086b |
hex | 13947ba618b |
1345528160651 has 2 divisors, whose sum is σ = 1345528160652. Its totient is φ = 1345528160650.
The previous prime is 1345528160629. The next prime is 1345528160653. The reversal of 1345528160651 is 1560618255431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1345528160651 - 234 = 1328348291467 is a prime.
It is a super-2 number, since 2×13455281606512 (a number of 25 digits) contains 22 as substring.
Together with 1345528160653, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1345528160596 and 1345528160605.
It is not a weakly prime, because it can be changed into another prime (1345528160653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672764080325 + 672764080326.
It is an arithmetic number, because the mean of its divisors is an integer number (672764080326).
Almost surely, 21345528160651 is an apocalyptic number.
1345528160651 is a deficient number, since it is larger than the sum of its proper divisors (1).
1345528160651 is an equidigital number, since it uses as much as digits as its factorization.
1345528160651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864000, while the sum is 47.
The spelling of 1345528160651 in words is "one trillion, three hundred forty-five billion, five hundred twenty-eight million, one hundred sixty thousand, six hundred fifty-one".
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