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13458311159 is a prime number
BaseRepresentation
bin11001000100010110…
…11000011111110111
31021201221012001011212
430202023120133313
5210030311424114
610103242152035
7654336520526
oct144213303767
937657161155
1013458311159
115786958407
1227371b261b
13136631b637
1491958c4bd
1553b7d2b3e
hex3222d87f7

13458311159 has 2 divisors, whose sum is σ = 13458311160. Its totient is φ = 13458311158.

The previous prime is 13458311081. The next prime is 13458311161. The reversal of 13458311159 is 95111385431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13458311159 is a prime.

It is a super-2 number, since 2×134583111592 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13458311161, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13458311179) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6729155579 + 6729155580.

It is an arithmetic number, because the mean of its divisors is an integer number (6729155580).

Almost surely, 213458311159 is an apocalyptic number.

13458311159 is a deficient number, since it is larger than the sum of its proper divisors (1).

13458311159 is an equidigital number, since it uses as much as digits as its factorization.

13458311159 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 64800, while the sum is 41.

The spelling of 13458311159 in words is "thirteen billion, four hundred fifty-eight million, three hundred eleven thousand, one hundred fifty-nine".