Base | Representation |
---|---|
bin | 101000000111100… |
… | …1010101111100001 |
3 | 10110211000200100212 |
4 | 1100033022233201 |
5 | 10224103402231 |
6 | 341324423505 |
7 | 45234054413 |
oct | 12017125741 |
9 | 3424020325 |
10 | 1346153441 |
11 | 630961006 |
12 | 3169a7b95 |
13 | 185b775c9 |
14 | caad69b3 |
15 | 7d2aa42b |
hex | 503cabe1 |
1346153441 has 2 divisors, whose sum is σ = 1346153442. Its totient is φ = 1346153440.
The previous prime is 1346153437. The next prime is 1346153467. The reversal of 1346153441 is 1443516431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1202633041 + 143520400 = 34679^2 + 11980^2 .
It is a cyclic number.
It is not a de Polignac number, because 1346153441 - 22 = 1346153437 is a prime.
It is a super-2 number, since 2×13461534412 = 3624258173432280962, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1346153398 and 1346153407.
It is not a weakly prime, because it can be changed into another prime (1346143441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 673076720 + 673076721.
It is an arithmetic number, because the mean of its divisors is an integer number (673076721).
Almost surely, 21346153441 is an apocalyptic number.
It is an amenable number.
1346153441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1346153441 is an equidigital number, since it uses as much as digits as its factorization.
1346153441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17280, while the sum is 32.
The square root of 1346153441 is about 36689.9637639505. The cubic root of 1346153441 is about 1104.1587588608.
Adding to 1346153441 its reverse (1443516431), we get a palindrome (2789669872).
The spelling of 1346153441 in words is "one billion, three hundred forty-six million, one hundred fifty-three thousand, four hundred forty-one".
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