Base | Representation |
---|---|
bin | 111110101100001001… |
… | …0000010100001000011 |
3 | 110212111020220011220021 |
4 | 1331120102002201003 |
5 | 4201203012010313 |
6 | 141502415154311 |
7 | 12504064361212 |
oct | 1753022024103 |
9 | 425436804807 |
10 | 134625110083 |
11 | 52104401862 |
12 | 22111815997 |
13 | c906174169 |
14 | 6731861079 |
15 | 377de1678d |
hex | 1f58482843 |
134625110083 has 2 divisors, whose sum is σ = 134625110084. Its totient is φ = 134625110082.
The previous prime is 134625109967. The next prime is 134625110117. The reversal of 134625110083 is 380011526431.
It is an a-pointer prime, because the next prime (134625110117) can be obtained adding 134625110083 to its sum of digits (34).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134625110083 is a prime.
It is not a weakly prime, because it can be changed into another prime (134625110383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67312555041 + 67312555042.
It is an arithmetic number, because the mean of its divisors is an integer number (67312555042).
Almost surely, 2134625110083 is an apocalyptic number.
134625110083 is a deficient number, since it is larger than the sum of its proper divisors (1).
134625110083 is an equidigital number, since it uses as much as digits as its factorization.
134625110083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 34.
The spelling of 134625110083 in words is "one hundred thirty-four billion, six hundred twenty-five million, one hundred ten thousand, eighty-three".
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