Base | Representation |
---|---|
bin | 111110101100001110… |
… | …0000001010001010111 |
3 | 110212111102211002211202 |
4 | 1331120130001101113 |
5 | 4201204144221143 |
6 | 141502551223115 |
7 | 12504125536061 |
oct | 1753034012127 |
9 | 425442732752 |
10 | 134627726423 |
11 | 52105929523 |
12 | 22112677a9b |
13 | c90687bca8 |
14 | 6731d42731 |
15 | 377e281ab8 |
hex | 1f58701457 |
134627726423 has 2 divisors, whose sum is σ = 134627726424. Its totient is φ = 134627726422.
The previous prime is 134627726419. The next prime is 134627726477. The reversal of 134627726423 is 324627726431.
It is a weak prime.
It is an emirp because it is prime and its reverse (324627726431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134627726423 - 22 = 134627726419 is a prime.
It is a super-2 number, since 2×1346277264232 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134627926423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67313863211 + 67313863212.
It is an arithmetic number, because the mean of its divisors is an integer number (67313863212).
Almost surely, 2134627726423 is an apocalyptic number.
134627726423 is a deficient number, since it is larger than the sum of its proper divisors (1).
134627726423 is an equidigital number, since it uses as much as digits as its factorization.
134627726423 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2032128, while the sum is 47.
The spelling of 134627726423 in words is "one hundred thirty-four billion, six hundred twenty-seven million, seven hundred twenty-six thousand, four hundred twenty-three".
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