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1346535320957 is a prime number
BaseRepresentation
bin10011100110000011110…
…000100110110101111101
311202201122100202200200222
4103212003300212311331
5134030201020232312
62510331221031125
7166166254244141
oct23460360466575
94681570680628
101346535320957
1147a0760a2632
12198b73b554a5
1399c93116708
144925bab3221
152505e538672
hex13983c26d7d

1346535320957 has 2 divisors, whose sum is σ = 1346535320958. Its totient is φ = 1346535320956.

The previous prime is 1346535320951. The next prime is 1346535320989. The reversal of 1346535320957 is 7590235356431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1036203879481 + 310331441476 = 1017941^2 + 557074^2 .

It is a cyclic number.

It is not a de Polignac number, because 1346535320957 - 210 = 1346535319933 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1346535320899 and 1346535320908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1346535320951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 673267660478 + 673267660479.

It is an arithmetic number, because the mean of its divisors is an integer number (673267660479).

Almost surely, 21346535320957 is an apocalyptic number.

It is an amenable number.

1346535320957 is a deficient number, since it is larger than the sum of its proper divisors (1).

1346535320957 is an equidigital number, since it uses as much as digits as its factorization.

1346535320957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10206000, while the sum is 53.

The spelling of 1346535320957 in words is "one trillion, three hundred forty-six billion, five hundred thirty-five million, three hundred twenty thousand, nine hundred fifty-seven".